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fix: Close #189556, gulp task do not display task name

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This commit is contained in:
yiliang114
2023-08-03 22:58:20 +08:00
parent 55fc1d298c
commit 76e25bad23
2 changed files with 21 additions and 7 deletions
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14
build/lib/compilation.ts
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@@ -95,7 +95,7 @@ function createCompile(src: string, build: boolean, emitError: boolean, transpil
export function transpileTask(src: string, out: string, swc: boolean): () => NodeJS.ReadWriteStream {
return function () {
const task = () => {
const transpile = createCompile(src, false, true, { swc });
const srcPipe = gulp.src(`${src}/**`, { base: `${src}` });
@@ -104,11 +104,14 @@ export function transpileTask(src: string, out: string, swc: boolean): () => Nod
.pipe(transpile())
.pipe(gulp.dest(out));
};
task.taskName = `transpile-${path.basename(src)}`;
return task;
}
export function compileTask(src: string, out: string, build: boolean, options: { disableMangle?: boolean } = {}): () => NodeJS.ReadWriteStream {
return function () {
const task = () => {
if (os.totalmem() < 4_000_000_000) {
throw new Error('compilation requires 4GB of RAM');
@@ -150,11 +153,14 @@ export function compileTask(src: string, out: string, build: boolean, options: {
.pipe(compile())
.pipe(gulp.dest(out));
};
task.taskName = `compile-${path.basename(src)}`;
return task;
}
export function watchTask(out: string, build: boolean): () => NodeJS.ReadWriteStream {
return function () {
const task = () => {
const compile = createCompile('src', build, false, false);
const src = gulp.src('src/**', { base: 'src' });
@@ -168,6 +174,8 @@ export function watchTask(out: string, build: boolean): () => NodeJS.ReadWriteSt
.pipe(util.incremental(compile, src, true))
.pipe(gulp.dest(out));
};
task.taskName = `watch-${path.basename(out)}`;
return task;
}
const REPO_SRC_FOLDER = path.join(__dirname, '../../src');