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https://github.com/pi-hole/dnsmasq.git
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f1204a875e
We want to sort such that the most recent/relevant tag is first and gets used to set the compiled-in version. The solution is far from general, but works for the tag formats used by dnsmasq. v2.84 sorts before v2.83, but v2.83 sorts before v2.83rc1 and 2.83rc1 sorts before v2.83test1
42 lines
1.4 KiB
Bash
Executable File
42 lines
1.4 KiB
Bash
Executable File
#!/bin/sh
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# Determine the version string to build into a binary.
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# When building in the git repository, we can use the output
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# of "git describe" which gives an unequivocal answer.
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#
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# Failing that, we use the contents of the VERSION file
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# which has a set of references substituted into it by git.
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# If we can find one which matches $v[0-9].* then we assume it's
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# a version-number tag, else we just use the whole string.
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# If there is more than one v[0-9].* tag, sort them and use the
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# first. The insane arguments to the sort command are to ensure
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# that, eg v2.64 comes before v2.63, but v2.63 comes before v2.63rc1
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# and v2.63rc1 comes before v2.63test1
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# Change directory to the toplevel source directory.
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if test -z "$1" || ! test -d "$1" || ! cd "$1"; then
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echo "$0: First argument $1 must be toplevel dir." >&2
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exit 1
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fi
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if which git >/dev/null 2>&1 && \
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([ -d .git ] || grep '^gitdir:' .git >/dev/null 2>&1) && \
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git describe >/dev/null 2>&1; then
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git describe | sed 's/^v//'
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elif grep '\$Format:%d\$' $1/VERSION >/dev/null 2>&1; then
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# unsubstituted VERSION, but no git available.
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echo UNKNOWN
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else
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vers=`cat $1/VERSION | sed 's/[(), ]/,/ g' | tr ',' '\n' | grep ^v[0-9]`
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if [ $? -eq 0 ]; then
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echo "${vers}" | sort -k1.2,1.5r -k 1.6,1.6 -k1.8,1.9r -k1.10,1.11r | head -n 1 | sed 's/^v//'
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else
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cat $1/VERSION
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fi
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fi
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exit 0
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